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5p^2-39p+28=0
a = 5; b = -39; c = +28;
Δ = b2-4ac
Δ = -392-4·5·28
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-31}{2*5}=\frac{8}{10} =4/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+31}{2*5}=\frac{70}{10} =7 $
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